๐Ÿงฎ System of Equations Solver

Two equations, two unknowns, every elimination step shown.

Equation 1: aโ‚x + bโ‚y = cโ‚

Equation 2: aโ‚‚x + bโ‚‚y = cโ‚‚

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Solution (x, y)

How to Use the System Solver

Write each equation in the form ax + by = c and enter the six coefficients. The solver uses elimination, shows every step, and flags parallel or identical lines.

1

Rearrange each equation to ax + by = c form if needed.

2

Enter the six coefficients aโ‚, bโ‚, cโ‚, aโ‚‚, bโ‚‚, cโ‚‚.

3

Read the solution and verify it in both original equations.

Elimination Method

Elimination cancels one variable by adding or subtracting scaled equations. For 3x + 2y = 12 and x โˆ’ y = 1: multiply the second by 2 to get 2x โˆ’ 2y = 2, add to the first: 5x = 14, so x = 2.8. Substitute back: 2.8 โˆ’ y = 1, so y = 1.8. The determinant D = aโ‚bโ‚‚ โˆ’ aโ‚‚bโ‚ predicts the outcome before you start: D โ‰  0 means one unique solution; D = 0 means parallel (no solution) or identical (infinite solutions).

Substitution Method

Solve one equation for one variable, then plug into the other. From x โˆ’ y = 1, x = y + 1. Substitute into 3x + 2y = 12: 3(y+1) + 2y = 12, so 5y = 9, y = 1.8, x = 2.8. Substitution is cleanest when a coefficient is 1 or โˆ’1. Both methods give the same answer; use whichever keeps the arithmetic simplest.

Three Possible Outcomes

One solution: lines cross at a single point (D โ‰  0). Most textbook problems. No solution: parallel lines (D = 0 but equations inconsistent, e.g. 0 = 5). Real-world: two pricing plans that never break even. Infinite solutions: same line twice (D = 0 and consistent, e.g. 0 = 0). The equations were redundant. Recognizing which case you are in before grinding arithmetic saves real time on exams.

Frequently Asked Questions

What is a system of equations?

Two or more equations sharing the same unknowns, solved together. The solution is the point (or points) satisfying all equations at once. Graphically, each linear equation is a line, and the solution is where the lines cross.

Substitution or elimination: which is better?

Both always work; pick by convenience. Substitution shines when one variable is already isolated (y = 2x + 1). Elimination shines when coefficients line up for easy cancellation (3x + 2y = 12 and 3x โˆ’ 2y = 4: add them). This solver shows the elimination path step by step.

What does "no solution" mean?

The lines are parallel: same slope, different intercept. Algebraically, elimination produces a false statement like 0 = 5. Example: x + y = 3 and x + y = 7 can never both be true. The solver detects this automatically.

What does "infinitely many solutions" mean?

The equations describe the same line: one is a multiple of the other. Elimination produces 0 = 0, true for every point on the line. Example: 2x + 2y = 6 and x + y = 3. Every point on the line y = 3 โˆ’ x is a solution.

How do I check my answer?

Plug the (x, y) values back into BOTH original equations. Each must balance. For x = 2, y = 1 in 3x + 2y = 8: 6 + 2 = 8 โœ“. A solution that fails either equation is wrong, usually from an arithmetic slip in the elimination step.