💿 Moment of Inertia of a Disk Calculator
Calculate I = (1/2)mr² for a solid disk or cylinder.
Result
How to Use This Calculator
This calculator finds the moment of inertia of a solid uniform disk about its central axis. Enter the mass and radius and the result appears in kg m^2.
Enter the mass of the disk in kilograms.
Enter the radius in meters, measured from the center to the outer edge.
Click Calculate. The moment of inertia appears in kg m^2.
This assumes a solid, uniform disk spinning about the axis through its center, perpendicular to its face.
Moment of Inertia of a Solid Disk
Moment of inertia measures resistance to angular acceleration: the rotational equivalent of mass. But unlike mass, it depends on where the mass sits. Mass far from the axis counts heavily because of the R^2 term, which is why a hoop of the same mass and radius has double the moment of inertia of a solid disk. Every bit of the hoop's mass rides at the rim, while the disk's mass is spread from center to edge.
The 1/2 factor is the result of adding up r^2 for every speck of mass across the disk's face. Specks near the hub contribute almost nothing, specks at the rim contribute fully, and the average lands exactly halfway. This is a solved integral, not an approximation, as long as the disk is uniform and thin relative to its radius.
Worked Example
Where This Comes Up
Disks are everywhere in rotating machinery: flywheels, grinding wheels, saw blades, hard drive platters, and pottery wheels. Engineers need the moment of inertia to size motors, because angular acceleration follows torque = I x alpha: double the moment of inertia and you need double the torque for the same spin-up time. Underestimating I burns out motors; overestimating wastes money on oversized ones.
Make sure you use the radius, not the diameter: entering the diameter quadruples the answer. And check the axis. This formula is only for the central axis perpendicular to the face. A disk tumbling end over end uses a different formula, I = (1/4)MR^2, so picture the rotation before you calculate.
Frequently Asked Questions
Why is the formula 1/2MR^2?
It comes from integrating r^2 dm over the disk's area. Mass near the center contributes little because r is small, while rim mass counts fully. The average works out to exactly half of MR^2.
Which resists spinning more, a disk or a hoop of the same mass and radius?
The hoop, with I = MR^2: exactly double the disk's 1/2MR^2. All of the hoop's mass sits at the maximum radius, while the disk's mass is spread inward.
What are the units?
Kilogram square meters (kg m^2).
Does the thickness of the disk matter?
Not for rotation about the central axis perpendicular to the face. Only the total mass and radius appear in the formula. Thickness matters for other axes.
What if the axis goes through the edge instead of the center?
Use the parallel axis theorem: I = I_center + Md^2. For an axis at the rim, d = R, giving I = 1/2MR^2 + MR^2 = 1.5MR^2.